During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235uf6 diffuses 0.4% faster than 238uf6. show the calculation that supports this value. the molar mass of 235uf6 = 235.043930 + 6 x 18.998403 = 349.034348 g/mol, and the molar mass of 238uf6 = 238.050788 + 6 x 18.998403 = 352.041206 g/mol.

The below calculations proves that the rate of diffusion of is 0.4 % faster than the rate of diffusion of

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

We are given:

Molar mass of

Molar mass of

By taking their ratio, we get:

From the above relation, it is clear that rate of effusion of is faster than

Difference in the rate of both the gases,

To calculate the percentage increase in the rate, we use the equation:

Putting values in above equation, we get:

The above calculations proves that the rate of diffusion of is 0.4 % faster than the rate of diffusion of

56 moles of   lieter in chemistry

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