The ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. in the first step of the ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. what is the maximum mass of h 2 o h2o that can be produced by combining 52.3 g 52.3 g of each reactant? 4 nh 3 ( g ) + 5 o 2 ( g ) ⟶ 4 no ( g ) + 6 h 2 o ( g )

35.3 g

Explanation:

From the balanced equation given we can say:

4 moles of NH3 reacts with 5 moles of O2 to give 6 moles of H2O.

4*17 g of NH3 reacts with 5*32 g of O2 to give 6*18 g of H2O.

68 g of NH3 reacts with 160 g of O2 to give 108 g of H2O.

Here the limiting reagent is O2 and excess reagent is NH3.

52.3 g of O2 will react with to give :

Hence the maximum mass of H2O that can be produced by 52.3 g of reactants is 35.3 g.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation: