What is the concentration of your solution?

(your unknown sample is known to be about 1 m, but you need to determine the concentration to 3 significant figures using titration. you should plan ahead so that you know approximately what volume of your sample you will need in order to use approximately 25 ml of 0.100 m sulfuric acid for the titration).

The volume of unknown sample would be 2.5 mL.

Explanation:

Given data:

Molarity of unknown sample=M₁= 1 M

Molarity of sulfuric acid = M₂= 0.100 M

Volume of sulfuric acid = V₂= 25 mL

Volume of unknown sample=V₁  = ?

Solution:

Formula:

M₁V₁   =  M₂V₂

Now we will put the values in formula:

1M × V₁   =  0.100 M × 25 mL

V₁   =  0.100 M × 25 mL / 1 M

V₁   = 2.5 mL

The volume of unknown sample would be 2.5 mL.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.