How many atoms of o are in 2.12 miles of no3

38.3×10²³ atoms of oxygen

Explanation:

Given data:

Moles of NO₃ = 2.12 mol

Atoms of oxygen = ?

Solution:

One mole of any substance contain 6.022 × 10²³ atoms.

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

One mole of NO₃ = 6.022 × 10²³ atoms

one molecule of NO₃ contain three atoms of oxygen thus in 2.12 moles number of oxygen atoms are:

2.12×3× 6.022 × 10²³ atoms = 38.3×10²³ atoms of oxygen

u i forgot the answer?

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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