How many liters are in 2.5 moles of chlorine gas?

Volume of the chlorine gas is 0,056 m³.

Explanation:

p × V = n × R ×T

p = 101325 Pa

n = 2,5 moles

R = 8,31446 J K⁻¹ moles⁻¹

T = 273,15 K

(standard conditions)

V = ( n × R × T ) / p = ( 2,5 moles × 8,31446 J K⁻¹ moles⁻¹ × 273,15 K) / 101325 Pa

V = 0,056 m³

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