subject
Chemistry, 12.12.2019 08:31 amandaiscool22

Achemist has a 12.5 liter sample of neon gas at 1.00 atm and 30 c. if the chemist compresses the sample to 10.5 liters and holds the pressure constant, what is the new temperature of the neon gas?

ansver
Answers: 3

Other questions on the subject: Chemistry

image
Chemistry, 22.06.2019 06:00, citlalli30
An atom of sodium-23 (atomic number = 11) has a positive charge of +1. give this information, how many electrons does it have? how many proteins and neutrons does this atom have
Answers: 2
image
Chemistry, 22.06.2019 19:00, ghernadez
Imagine that a new planet is discovered with two moons of equal mass: moon a and moon b. the mass of the new planet is greater than the combined mass of its moons. moon a is farther away from the new planet than moon b. what is the planet's gravitational pull on moon a compared to the planet's gravitational pull on moon b? the planet's gravity repels moon a with a greater force than it repels moon b, which is why moon a is farther away. the gravitational pull on moon b is greater than on moon a because moon b is closer to the new planet than moon a. the gravitational pull on moon b is greater than on moon a because moon b is farther away from the new planet than moon a. the gravitational pull on moon a is the same as the gravitational pull on moon b because distance does not affect the planet's gravity.
Answers: 1
image
Chemistry, 22.06.2019 21:50, BookandScienceNerd
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
Answers: 1
image
Chemistry, 23.06.2019 01:20, hflores0001
How can parts of a solution be separated by chromatography?
Answers: 1
You know the right answer?
Achemist has a 12.5 liter sample of neon gas at 1.00 atm and 30 c. if the chemist compresses the sam...

Questions in other subjects: