What mass of co2 gas occupies a 32.5 dm cubed flask at 32°c in 104.7 kpa pressure

Mass = 59.4 g

Explanation:

Given data:

Volume of CO₂ =32.5 dm³

Temperature = 32°C

Pressure = 104.7 KPa

Mass of  CO₂  = ?

Solution:

32+273 = 305 K

104.7/101 = 1.04 atm

PV = nRT

n = PV/RT

n = 1.04 atm×32.5 L/ 0.0821 atm. L/mol.K×305 K

n = 33.8 /25.04 /mol

n = 1.35

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.35 mol × 44 g/mol

Mass = 59.4 g

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

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