What is the volume of 0.05 mol of neon gas at stp?

= 1.12 L

We are given;

We are required to calculate the volume;

Therefore;

1 mole of Neon gas = 22.4 L

Thus;

Volume = Moles of the gas × molar gas volume

             = 0.05 mol × 22.4 L/mol

             = 1.12 L

Thus, the volume of neon gas at STP is 1.12 L

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