If i have 27l of a 0.003 m solution of salt water, how many molecules of salt do i have?

no. of molecules of salt =  5.046 x 10²²

Explanation:

Data given:

Volume of the Solution = 27 L

Molarity of the Solution = 0.003

Number of molecules of salt = ?

Solution:

First find number of moles of salt

Formula used

                      Molarity = moles of solute / L of solution

Rearrange the above equation

                      moles of solute = Molarity x L of Solution

Put values in above equation

                    moles of solute = 0.003 x 27 L

                    moles of solute = 0.081 moles

Now we can find the number of molecules of salt

Formula used to find no. of molecules

      no. of moles = no. of molecules / Avogadro's number

Avogadro's number = 6.23 x 10²³

Now rearrange the above equation

     no. of molecules = no. of moles x Avogadro's number . . . . . . . (1)

Put values in Equation 1

      no. of molecules =  0.081 moles x 6.23 x 10²³

      no. of molecules =  5.046 x 10²²

So,

no. of molecules of salt =  5.046 x 10²²

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

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