Given that kp = 3.5 x 10-4 for the reaction 2 co(g) < => c(graphite) + co2(g), what is the partial pressure of co2(g) at equilibrium if initially 4.00 atm of co(g) is in contact with graphite?

The partial pressure of carbon dioxide at equilibrium is 0.0056 atm

Explanation:

The given chemical equation follows:

Initial:             4.00

At eqllm:       4.00-2x        x                 x

The expression of for above reaction follows:

The partial pressure of pure solids and liquids are taken as 1 in the equilibrium constant expression.

We are given:

Putting values in above expression, we get:

Neglecting the value of x = 718.28 because equilibrium pressure cannot be greater than initial pressure

Partial pressure of = 0.0056 atm

Hence, the partial pressure of carbon dioxide at equilibrium is 0.0056 atm

gas

explanation:

smoke is the matter of a gas