Suppose a buffer solution is made from formic acid (hcho2) and sodium formate (nacho2). what isthe net ionic equation for the reaction that occurs when a small amount of sodium hydroxide is added to the buffer? a)naoh(aq)+ hcho2(aq) -> nacho2(aq) + h2o(l)b) na+(aq) + hcho2(aq) -> nah(aq) + hco2+(aq)c) oh-(aq) + hcho2(aq) -> cho2-(aq) + h2o(l)d) h3o+(aq) + oh-(aq) -> 2h2o(l)e) naoh(aq) + h3o+(aq) na+(aq) + 2h2o(l)

C) OH⁻(aq) + HCHO₂(aq) → CHO₂⁻(aq) + H₂O(l)

Explanation:

The net ionic equation is a chemical equation for a reaction that lists only those species participating in the reaction.

When there is an addition of base in a buffer, the acid will react with the base to produce water and conjugate base. Thus, the reaction is:

OH⁻(aq) + HCHO₂(aq) → CHO₂⁻(aq) + H₂O(l)

-You don't write the sodium of NaOH because is not involved in the reaction-

I hope it helps!

the answer is c.the valence of the atoms combine .