The vapor pressure of pure water at 15 °c is 12.8 mm hg. what is the equilibrium vapor pressure of water above a mixture of 72.0 g ethanol (ch3ch2oh, molar mass = 46.07 g/mol) and 22.0 g water?

The vapor pressure of water above this mixture is 5.6173 mm Hg.

Explanation:

We need to find the vapour pressure due to water in the solution.

According to Raoult's law ,

The vapour pressure due to any one component alone is the product of it's pure vapour pressure and it's mole fraction in the solution .

i.e ,

where ,

∴

∴

[tex]Y_A=0.43885*12.8\\Y_A=5.6173 mm Hg[tex]

The vapor pressure of water above this mixture is 5.6173 mm Hg.

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

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