When a metal was exposed to light at a frequency of 3.64× 1015 s–1, electrons were emitted with a kinetic energy of 5.80× 10–19 j. what is the maximum number of electrons that could be ejected from this metal by a burst of light (at some other frequency) with a total energy of 8.66× 10–7 j?

Answer :  The maximum number of electrons released

Explanation : Given,

Frequency =

Kinetic energy =

Total energy =

First we have to calculate the work function of the metal.

Formula used :

where,

K.E = kinetic energy

h = Planck's constant =

= frequency  

w = work function

Now put all the given values in this formula, we get the work function of the metal.

By rearranging the terms, we get

Therefore, the works function of the metal is,

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released =

Therefore, the maximum number of electrons released is

elements

explanation:

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the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.