![\begin{array}{rcl}Q & = & \dfrac{\text{[Cd$^{2+}$]}}{\text{[Ni}^{2+}]}\\\\1.14 \times 10^{-3} & = & \dfrac{x}{1.00}\\\\x& = & 1.14 \times 10^{-3}\\\end{array}\\\text{The concentration of Cd$^{2+}$ is $\large \boxed{\textbf{1.14 $\times \mathbf{10^{-3}}$ mol/L}}$}](/tpl/images/0408/2929/986a6.png)
Calculate the cd^2+ concentration in the following cell if ecell = 0.23
cd | cd^2+ (x m)...
Chemistry, 07.12.2019 21:31 hewonabi123
Calculate the cd^2+ concentration in the following cell if ecell = 0.23
cd | cd^2+ (x m) || ni^2+ (1.00 m) | ni
Answers: 2
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