For the reaction, calculate how many moles of the product form when 2.05 mol of o2 completely reacts.
assume that there is more than enough of the other reactant.
2h2(g)+o2(g)→2h2o(l)

n H2O(l) = 4.1 mol

Explanation:

2H2(g) + O2(g) → 2H2O(l)

∴ n O2(g) = 2.05 mol

⇒ n H2O(l) = ( 2.05 mol O2 )×( 2 mol H2O / mol O2 )

⇒ n H2O(l) = 4.1 mol

It decreases by 4 is your answer mark brainliest 

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