What is the energy of a photon of red light that has a frequency of 4.48 x 10^14hz?

E = 29.7× 10⁻²⁰  j

Explanation:

Given data;

Frequency of light = 4.48 × 10¹⁴ Hz

Energy of photon = ?

Solution:

Formula:

E = h.f

E = energy of photon

h = planck's constant

f = frequency

E = h.f

E = 6.63 × 10⁻³⁴ Kg.m² /s × 4.48 × 10¹⁴ s⁻¹

E = 29.7× 10⁻²⁰ Kg.m²/s²

Kg.m²/s² = j

E = 29.7× 10⁻²⁰  j

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml