![K_{C} = \frac{[H_{2}]^8[S_{8}]}{[H_{2}S]^{8}} \\\\K_{C} = \frac{0.4^{8} * 0.750}{0.25^{8}}\\\\](/tpl/images/0401/7917/3358b.png)
![K_c = \frac{{[H_2]}^8[S_8]}{{[H_2S]}^8}\\K_c = \frac{0.4^8 \times 0.75}{0.25^8}\\K_c = \frac{4.91 \times 10^{-4}}{1.52 \times 10^{-5}}\\K_c = 32.3](/tpl/images/0401/7917/f47c1.png)
For the reaction shown here
8h2s(g) > < 8h2(g) + s8(g)
the equlibriu...
Chemistry, 03.12.2019 23:31 muravyevaarina
For the reaction shown here
8h2s(g) > < 8h2(g) + s8(g)
the equlibrium concentrations were found to be
[h2s] = 0.250 m
[h2] = 0.400 m
[s8] = 0.750 m
what is the equilibrium constant for this reaction?
kc =
Answers: 1
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