At a certain temperature, 0.760 mol so3 is placed in a 1.50 l container. 2so3(g) = 2so2(g) + o2(g)at equilibrium, 0.130 mol o2 is present. calculate kc.

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

yes it is balanced