Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 21.3 and the temperature is 37.0 ° c ? δ g ° ' for the reaction is − 16.7 kj/mol .

The Gibbs free energy of the reaction is -8.82 kJ/mol

Explanation:

The equation used to Gibbs free energy of the reaction follows:

where,

= free energy of the reaction

= standard Gibbs free energy = -16.7 kJ/mol = -16700 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant =

T = Temperature =

= Ratio of concentration of products and reactants = 21.3

Putting values in above equation, we get:

Hence, the Gibbs free energy of the reaction is -8.82 kJ/mol

the answer is d   for sure : )

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