10.0 g of ammonium nitrate (? hsoln = 25.7 kj/mol, molar mass = 80.0 g/mol) dissolves in 100.0 g of water.

what is the change in temperature of the solution?

assume the specific heat capacity of the solution is 4.2 j

The change in temperature = 7.65 °C

Explanation:

Step 1: Data given

10.0 grams of ammonium nitrate dissolves in 100.0 grams of water

Hsoln = 25.7 kJ/mol

Molar mass = 80.04 g/mol

Heat capacity of the solution = 4.2 J

Step 2: Calculate moles  ammonium nitrate

Moles = mass / molar mass

Moles = 10.0 grams / 80.04 g/mol

Moles =0.125 moles

Step 3: Calculate q

q = 25.7 kJ/mol * 0.125 moles

q = 3.2125 kJ = 3212.5 J

Step 4: Calculate change in temperature

q = m*c*ΔT

3212.5 J = 100g *4.2 J * ΔT

ΔT= 7.65

The change in temperature = 7.65 °C

the answer is c. nacl

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