What mass of feso4^2- x 6h20 (molar mass=260g/mol) is required to produce 500 ml of a .10m iron (ii) sulfate solution.
a.) 9g
b.) 13g
c.) 36g
d.) 72g

The correct option is: B. 13g

Explanation:

Given: Molar mass of iron (II) sulfate: m = 260g/mol,

Molarity of iron (II) sulfate solution: M =  0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L           (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

Molarity:

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

∴ Molarity of iron (II) sulfate solution:  

⇒  

⇒  

⇒  mass of iron (II) sulfate taken:

Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.

answer; /// the amount of material dissolved in a measure of liquid(concentration) the above statement is (true); /// good luck

they are all solids.