Given the partial equation ? mno4−+ ? so32− → ? mn2++ ? so42− what must the coefficients be so that the electrons are balanced? enter the equation coefficients in order separated by commas (e. g., 2,2,1,4, where 1 indicates the absence of a coefficient).

The coefficients should be: 2, 5, 2, 5

Explanation:

Given redox reaction: MnO₄⁻ + SO₃²⁻ → Mn²⁺+ SO₄²⁻

To balance the given redox reaction in acidic medium, the oxidation and the reduction half-reactions should be balanced first.

Reduction half-reaction: MnO₄⁻ → Mn²⁺

Oxidation state of Mn in MnO₄⁻ is +7 and the oxidation state of Mn in Mn²⁺ is +2. Therefore, Mn accepts 5e⁻ to get reduced from +7 to +2 oxidation state.

⇒ MnO₄⁻ + 5e⁻ → Mn²⁺

Now the total charge on reactant side is (-6) and the total charge on product side is +2. Therefore, to balance the total charge, 8H⁺ must be added to the reactant side.

⇒ MnO₄⁻ + 5e⁻ + 8H⁺ → Mn²⁺

To balance the number of hydrogen and oxygen atoms, 4H₂O must be added to the product side.

⇒ MnO₄⁻ + 5e⁻ + 8H⁺ → Mn²⁺ + 4H₂O               equation 1

Oxidation half-reaction: SO₃²⁻ → SO₄²⁻

Oxidation state of S in SO₃²⁻ is +4 and the oxidation state of S in SO₄²⁻ is +6. Therefore, S loses 2e⁻ to get oxidized from +4 to +6 oxidation state.

⇒ SO₃²⁻ → SO₄²⁻ + 2e⁻

Now the total charge on reactant side is (-2) and the total charge on product side is (-4). Therefore, to balance the total charge, 2H⁺ must be added to the product side.

⇒ SO₃²⁻ → SO₄²⁻ + 2e⁻ + 2H⁺

To balance the number of hydrogen and oxygen atoms, 1 H₂O must be added to the reactant side.

⇒ SO₃²⁻ + H₂O → SO₄²⁻ + 2e⁻ + 2H⁺                equation 2

Now, to cancel the electrons transferred, equation (1) is multiplied by 2 and equation (2) is multiplied by 5.

Balanced Reduction half-reaction:

MnO₄⁻ + 5e⁻ + 8H⁺ → Mn²⁺ + 4H₂O ] × 2

⇒ 2MnO₄⁻ + 10e⁻ + 16H⁺ → 2Mn²⁺ + 8H₂O                equation 3

Balanced Oxidation half-reaction:

SO₃²⁻ + H₂O → SO₄²⁻ + 2e⁻ + 2H⁺ ] × 5

⇒ 5SO₃²⁻ + 5H₂O → 5SO₄²⁻ + 10e⁻ + 10H⁺                  equation 4  

Now adding equation 3 and 4, to obtain the overall balanced redox reaction:

2MnO₄⁻ + 5SO₃²⁻ + 6H⁺ → 2Mn²⁺ + 5SO₄²⁻ + 3H₂O

Therefore, the coefficients should be: 2, 5, 2, 5

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.