What is the value for the reaction: n2(g) + 2 o2(g) --> n2o4(g) in terms of k values from the reactions:

½ n2(g) + ½ o2(g) > no(g)

k1

2 no(g) + o2(g) > n2o4(g)

k2

k1^2 + k2
2 k1 x k2
k1^2 x k2
k1 + k2

Answer : The correct expression will be:

Explanation :

The chemical reactions are :

(1)

(2)

The final chemical reaction is :

Now we have to calculate the value of for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.