Consider a solution containing 0.181 m lead (ii) ions and 0.174 m mercury(ii) ions. calculate the maximum concentration of sulfide ions that can be in solution without precipitating any lead ions. ksp: lead sulfide is 3.4 × 10−28; mercury(ii) sulfide is 4.0 × 10−53.

Achemical equilibrium between gaseous reactants and products is shown. n2(g) + 3h2(g) ⇌ 2nh3(g) how will the reaction be affected if the pressure on the system is increased? it will shift toward the reactant side as there is lower pressure on the reactant side. it will shift toward the product side as there is higher pressure on the product side. it will shift toward the reactant side as there are a greater number of moles of gas on the reactant side. it will shift toward the product side as there are a fewer number of moles of gas on the product side.