Draw the lewis structure of osf 4 where the formal charge is zero on each atom. the sulfur atom is the central atom in the structure, and it is bonded to the oxygen atom and each of the four fluorine atoms.

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.