Asample of carbon monoxide gas occupies 150.0ml at 25.0 degrees celsius. it is then cooled at a constant pressure until it occupies 100.0ml. what is the new temperature in degrees celsius?

T₂ = 16.7  °C

Explanation:

Given data:

Initial volume = 150.0 mL

Temperature = 25.0 °C

Final volume = 100 mL

Final temperature = ?

Solution:

V₁ /T₁ = V₂/T₂

T₂ = V₂ . T₁/V₁

T₂ = 100 mL .25 °C / 150.0 mL

T₂ = 2500 mL.  °C / 150.0 mL

T₂ = 16.7  °C

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