The solubility of gold (iii) chloride is 1.00x10^-4 g/l. what is the ksp for aucl3 (molar mass=303.3 g/mol)
a.) 1.00x10^-16
b.) 2.7x10^-15
c.) 1.2x10^-26
d.) 3.2x10^-25

The of gold (III) chloride is

Explanation:

We are given:

Solubility of gold (III) chloride =

Molar mass of gold (III) chloride = 303.3 g/mol

To calculate the solubility in mol/L, we divide the given solubility (in g/L) with molar mass, we get:

Putting values in above equation, we get:

The balanced equilibrium reaction for the ionization of gold (III) chloride follows:

                s       3s

The expression for solubility constant for this reaction will be:

We are given:

Putting values in above equation, we get:

Hence, the of gold (III) chloride is

explanation:

i think option no d is the correct answer