40.00 ml of 0.10 m koh solution is titrated by 30.00 ml of 0.10 m hcl (adding hcl to koh). what is the ph of the solution in the erlenmeyer flask after the titration? assume that the volumes of the solutions are additive.

Explanation:

The alkaline solution:

40 ml of 0.1 M KOH

The acid solution:

30 ml of 0.1 M HCl

The neutralization reaction:

For 1 mol of HCl, 1 mol of KOH is consumed. If 0.003 mol of HCl are added, 0.003 mol of KOH reacted.

After titration:

Concentration (don't forget to add the volumes)

Calcualtion of the pOH:

For the pH:

hope you got the answer

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