Organic chem

name the following compounds:
see attachments for questions

a) 3-methylhex-1,3-diene

b) 1-ethyl-4-methyl-2prpylbenzene

c) 2-bromo-3-chloro-2-floropentane

Explanation:

These both are organic compound.

One is open chain compound, while the other is a ring containing compound.

There are some basic IUPAC rules according to which the three compounds will be named:

1. Nomenclature of Compound (a)

Name according to IUPAC nomenclature.

These IUPAC nomenclature rule is as follow

1.Select the longest chain

2.Select the chain have double or triple bond on the lowest number     carbon

3.Select the chain have substitution on the lowest number carbon

4.Starts from that side that have lowest carbon number have substitution

5.Starts the name in Alphabetical order As E comes first form M

So

•It has 6 carbon

•Select the chain have double on the lowest number carbon.

•This have 2 double bond on position 1 and position 3 and the name end at diene.

•The methyl attach on carbon number 3

So the name for this compound is

3-methylhex-1,3-diene

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2. Nomenclature of Compound ( b )

This is an aromatic compound. its a benzene derivative

So the name for this compound is

1-ethyl-4-methyl-2prpylbenzene

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3. Nomenclature of Compound ( c )

•This compound has 5 carbons long chain and name as pentane

•Bromine and fluorine attached on carbon  number 2 and named as bromo and floro

•One chlorine is attached on carbon number 3 and name as chloro

Now start the name in Alphabetical order As E comes first form M

So the name of this compound is

2-bromo-3-chloro-2-floropentane

it is a good conductor

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml