Why is a terminal alkyne favored when sodium amide (nanh2) is used in an elimination reaction with 2,3-dichlorohexane? a. the resonance favors the formation of the terminal rather than internal alkyne. b. the positions of the cl atoms induce the net formation of the terminal alkyne. c. the strong base deprotonates the terminal alkyne and removes it from the equilibrium. d. the terminal alkyne is more stable than the internal alkyne and is naturally the favored product. e. the terminal alkyne is not favored in this reaction.

explanation:

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol