Calculate the standard cell potential at 25 ∘c for the reactionx(s)+2y+(aq)→x2+(aq)+2y(s)w here δh∘ = -829 kj and δs∘ = -367 j/k

The standard cell potential at 25 ∘C for the reaction is 2.72 Volts.

Explanation:

Δ°G = Δ°H - TΔ°S (Gibb's equation)

Δ°G =  Gibbs free energy

Δ°H = Enthalpy of the reaction at temperature T

Δ°S = Entropy of the reaction at temperature T

n = number of electrons transferred

F = Faraday's constant = 96500 C

= standard electrode potential of the cell

We have:

Δ°H = -829 kJ = -829000 J

Δ°S = -367 J/K

T = 25 C = 298.15 K

n = 2

The standard cell potential at 25 ∘C for the reaction is 2.72 Volts.

i believe it is 40–40–20%

explanation: