Ammonia forms when hydrogen gas reacts with nitrogen gas according to the equation below. if equal moles of nitrogen and hydrogen are combined, the maximum number of moles of ammonia that could be formed will be equal to: two thirds the number of moles of hydrogenthe number of moles of hydrogenthe number of moles of nitrogentwice the number of moles of nitrogen

The number of moles NH3 produced is two thirds of moles of hydrogen.

Explanation:

Step 1: Data given

Number of moles H2 = Number of moles N2

Step 2: The balanced equation

3H2 + N2 → 2NH3

Step 3: Calculate mol NH3 produced

For 1 mol N2 consumed, we need 3 moles of H2, to produce 2 mol of NH3

H2 is the limiting reactant. This will be completely consumed.

N2 is in excess. There will be consumed 1/3 of moles of H2

The mole ratio H2:NH3 = 3:2

The number of moles NH3 produced is two thirds of moles hydrogen.

The number of moles N2 is one third of moles hydrogen.

step-by-step explanation:

whole numbers, zero or greater

the answer to your question is c.

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