Chemistry, 17.09.2019 19:50 wendyyy1214

Astudent determines that she used 0.0665 mol of sodium hydroxide (naoh) to completely titrate 25.00 ml of sulfuric acid solution (h2so4). what is the molarity of the sulfuric acid?

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titration is an analysis used for determining the concentration of one solution especially an acidic or basic solution by taking advantage of its equivalence point when it is neutralized by a standardized solution of its opposite solution. the reaction for this titration is:

2naoh +2h2so4 = na2so4 +2h2o

0.0665 mol naoh (2 mol h2so4/ 2mol naoh) / .025 l solution = 2.66 m h2so4

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

Answer from: Quest

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Astudent determines that she used 0.0665 mol of sodium hydroxide (naoh) to completely titrate 25.00...