Given only the following data, what can be said about the following reaction? 3h2(g) + n2(> 2nh3(g) δh=-92kja.) the enthalpy of products is greater than the enthalpy of reactantsb.) the total bond energies of products are greater than the total bond energies of reactantsc.) the reaction is very fastd.) nitrogen and hydrogen are very stable bonds compared to the bonds of ammonia

D.) Nitrogen and Hydrogen are very stable bonds compared to the bonds of ammonia.

Explanation:

For the reaction:

3H₂(g) + N₂(g) → 2NH₃(g)

The enthalpy change is ΔH = -92kJ

This enthalpy change is defined as the enthalpy of products - the enthalpy of reactants. As the enthalpy is <0, The enthalpy of products is lower than the enthalpy of reactants.

Also, it is possible to obtain the enthalpy change from the bond energies of products - bond energies of reactants, thus, The total bond energies of products are lower than the total bond energies of reactants.

The rate of the reaction couldn't be determined using ΔH.

As the bond energy of ammonia is lower than bonds of nitrogen and hydrogen, D. Nitrogen and Hydrogen are very stable bonds compared to the bonds of ammonia.

I hope it helps!

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g