Asample of an ideal gas has a volume of 3.10 l at 13.80°c and 1.30atm. what is the volume of the gas at 25.00°c and 0.988atm

4.24 L

Explanation:

We are given;

Initial Volume, V1 is 3.10 LInitial temperature, T1 is 13.80°C

But, K = °C + 273.15

Thus, Initial temperature, T1 is 286.95 KInitial pressure, P1 is 1.30 atm New temperature, T2 is 25°C or 298.15 KNew pressure, P2 is 0.988 atm

We are required to calculate the new volume;

We are going to use the combined gas law;According to the combined gas law;

Rearranging the formula;

Therefore;

Therefore, the new volume of the gas sample is 4.24 L

Ido not understand.