Chemistry, 26.12.2019 18:31 ptrlvn01

Which ion was formed by providing the second ionization energy to remove an electron? ca2+ n3– fe3+ s2–

Answers: 1

Show answers

Answers

Answer from: fefe57

Ca²⁺

Explanation:

Ionization energy is defined as the minimum amount of energy required to knock out the electron from valence shell of an atom in its gaseous state. While, second Ionization energy is defined as the amount of energy required to knock out the second electron from an ion containing +1 charge in gaseous state.

Among given options Ca²⁺ is the correct choice because the calcium has lost two electrons i.e. first electron was removed by providing first ionization energy i.e.

Ca + 1st IE → Ca¹⁺ + 1 e⁻

and second electron is was removed by providing second ionization energy i.e.

Ca ¹⁺ + 2nd IE → Ca²⁺ + 1 e⁻

Answer from: orlando19882000

$\boxed{{\text{C}}{{\text{a}}^{{\text{2 + }}}}}$ is formed by providing the second ionization energy to remove an electron.

Further Explanation:

The energy that is needed to remove the most loosely bound valence electrons from the isolated neutral gaseous atom is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.

Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as ${\text{I}}{{\text{E}}_{\text{1}}}$ . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy $\left( {{\text{I}}{{\text{E}}_{\text{2}}}} \right)$ and so on.

The neutral atom corresponding to ${\text{C}}{{\text{a}}^{2 + }}$ is calcium. If second ionization energy is supplied to calcium atom, it results in the removal of two electrons and thus ${\text{C}}{{\text{a}}^{2 + }}$ is formed. So ${\text{C}}{{\text{a}}^{2 + }}$ can be formed by providing second ionization energy. to the neutral atom.

The neutral atom corresponding to ${{\text{N}}^{3 - }}$ is nitrogen. If second ionization energy is supplied to nitrogen, it results in the formation of ${{\text{N}}^{2 + }}$ , not ${{\text{N}}^{3 - }}$ . So ${{\text{N}}^{3 - }}$ cannot be formed by providing the second ionization energy to the neutral atom.

The neutral atom corresponding to ${\text{F}}{{\text{e}}^{3 + }}$ is iron. If second ionization energy is supplied to the iron atom, it results in the formation of ${\text{F}}{{\text{e}}^{2 + }}$ , not ${\text{F}}{{\text{e}}^{3 + }}$ . So ${\text{F}}{{\text{e}}^{3 + }}$ cannot be formed by providing the second ionization energy to the neutral atom.

The neutral atom corresponding to ${{\text{S}}^{2 - }}$ is sulfur. If second ionization energy is supplied to the sulfur atom, it results in the formation of ${{\text{S}}^{2 + }}$ , not ${{\text{S}}^{2 - }}$ . So ${{\text{S}}^{2 - }}$ cannot be formed by providing the second ionization energy to the neutral atom.

Therefore, the only ion that can be formed by supplying the second ionization energy is ${\text{C}}{{\text{a}}^{2 + }}$ .

Learn more:

1. Which is the oxidation-reduction reaction:

link

2. What is the mass of 1 mole of viruses: link

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Periodic classification of elements

Keywords: second ionization energy, Ca2+, N3-, Fe3+, S2-, IE1, IE2, first electron, second electron, neutral atom., nitrogen, calcium, iron, sulfur.

Which ion was formed by providing the second ionization energy to remove an electron? ca2+ n3– fe3+

Answer from: Quest

Answer : option a) 84explanation :

considering the question as per the attachment

$^{222}_{86}> ^{218}_{84}po+^{4}_{2}he$

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.

Answer from: Quest

(no3)⁻n has oxidation number x,o has oxidation number -2.(x*1 -2*3) charge of the nitrate ion, and we know that charge of the nitrate ion =-1.so,(x*1 -2*3) =-1x-6=-1x=+5answer a. +5.