Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 17. g of octane is mixed with 93.0 g of oxygen. calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. be sure your answer has the correct number of significant digits.

52.8 g of

Explanation:

To calculate the moles, we use the equation:

a) moles of octane

b) moles of oxygen

According to stoichiometry :

2 moles of require 25 moles of

Thus 0.150 moles of   require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 2 moles of give =  16 moles of

Thus 0.150 moles of give =  of

Mass of

Thus 52.8 g of will be produced from the given masses of both reactants.