What is the atmospheric pressure when a liquid is boiling at its normal boiling point? a. 505 kpa b. 101.3 kpa c. 202 kpa

The correct answer is B. 101.3 kPa

Explanation:

The boiling point  of a liquid corresponds to the temperature at which the vapor pressure is equal to the normal atmospheric pressure. This value corresponds to: 101.3 kPa / 1013 hectoPa / 760mmHg.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :