What is the concentration in molarity of a solution made using 10.0 grams of kcl in 300.0 ml of water?
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From Molarity=concentration/molar mass

Concentration=10/0.3dm³

33.33g/dm³

Molar mass=H2O=18g/mol

Molarity=1.852mol/dm³

0. 446 mol L−1

Explanation:

For Molarity, we must know the following things  

•the number of moles of solute present in solution

•the total volume of the solution

we know the mass of one mole of potassium chloride = 74.55 g  

Number of moles = Given Mass of substance / Mass of one mole

No of moles = 10 / 74.55

                   = 0.134 moles  

Now we know that  molarity is expressed per liter of solution. Since you dissolve 0.134 moles of potassium chloride in 300. mL of solution, you can say that 1.0 L will contain

For 300 ml of solution, no of moles are = 0.134 moles

For 1 ml of solution, no of moles are = 0.134/300 moles

For 1(1000) ml of solution, no of moles are=  0.134/300 x 1000

                                                                 = 0.446 moles/ L

Answer is =0. 446 mol L−1

the dependant variable is spilled water

the independent is the heat

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