What is the concentration in molarity of a solution made using 50.0 grams of c6h12o6 in 300.0 ml of water?
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concentration in Molarity it's actually Molarity

Molarity=concentration/molar mass

Concentration=50g/0.3dm³=166.67g/dm³

Molar mass=180g/mol

Molarity=0.926mol/dm³

Answer is =0. 925 mol L−1

Explanation:

C₆H₁₂O₆ is formula of Glucose  

For Molarity, we must know the following things  

•the number of moles of solute present in solution

•the total volume of the solution

we know the mass of one mole of Glucose = 180.156 g/mol

Number of moles = Given Mass of substance / Mass of one mole

No of moles = 50g / 180.156 g/mol

                   = 0.277 moles  

Now we know that  molarity is expressed per liter of solution. Since you dissolve 0.277 moles of potassium chloride in 300. mL of solution, you can say that 1.0 L will contain

For 300 ml of solution, no of moles are = 0.277 moles

For 1 ml of solution, no of moles are = 0.277/300 moles

For 1(1000) ml of solution, no of moles are=  0. 277/300 x 1000

                                                                 = 0.925 moles/ L

Answer is =0. 925 mol L−1

it would be a gas formation