Use the standard reduction potentials to find the equilibrium constant for each of the following reactions at 25°c.
(a) 5 fe2+(aq) + mno4? (aq) + 8 h+(aq) < > mn2+(aq) + 4 h2o(l) + 5 fe3+(aq)
(b) 2 ce4+(aq) + 2 cl ? (aq) < > cl2(g) + 2 ce3+(aq)
(c) br2(l) + 2 i ? (aq) < > 2 br? (aq) + i2(s)

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied