An aqueous solution is prepared by dissolving 15.6 g of cu(no3)2 ⋅ 6 h2o in water and diluting to 345 ml of solution. what is the molarity of the no3- ion in this solution?

a. 0.417 m
b. 0.121 m
c. 0.306 m
d. 0563 m
e. 0.834 m

The molarity of ions in the solution is 0.306 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Mass of solute = 15.6 g

Molar mass of = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

As, 1 mole of produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of ions = (2 × 0.153) = 0.306 M

Hence, the molarity of ions in the solution is 0.306 M

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."