Chemistry, 21.11.2019 20:31 jillianbarnes2565
An electron in the 7th energy level of the h atom drops to the 3th energy level. in other words an electron in an excited state drops to a less excited state. what is the energy (in j) of the emitted photon? the energy of an electron in the nth level
Answers: 3
= 7, 
= 3![\Delta E = -2.178 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](/tpl/images/0384/9623/e92a6.png)
![-2.178 \times 10^{-18} J \times (1)^{2}[\frac{1}{(3)^{2}} - \frac{1}{(7)^{2}}]](/tpl/images/0384/9623/c0081.png)
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