If 7.5 g of carbon is burned completely, what volume of carbon dioxide gas is released at stp?

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The volume of carbon dioxide produced is 14L

Explanation:

Step 1: Data given

Mass of carbon = 7.5 grams

Molar mass of Carbon = 12 g/mol

STP = 1 mole of any gas occupies 22.4 liters

This means 12 grams of carbon occupies 22.4 liters

Step 2: The equation

C + O2 → CO2

For 1 mole Carbon consumed, we need 1 mole oxygen to produce 1 mole CO2. This is a 1:1 mol ratio.

7.5 grams of carbon will occupy (7.5/12)*22.4L = 14 liters

7.5 g of carbon is burned completely, 14 liters of carbon dioxide are released.

This is because at STP, 1 mole of any gas occupies 22.4 liters of volume and 7.5 grams of carbon is 0.6 mole of carbon. Since carbon produces carbon dioxide in a 1:1 ratio when burned, it means that 0.6 mole of carbon dioxide will be produced.

The volume of carbon dioxide produced is 14L

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explanation:

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