If 39.0 g of c6h6 reacts with excess chlorine and produces 30.0 g of c6h5cl in the reaction c6h6 + cl2 → c6h5cl + hcl , what is the percent yield of c6h5cl? 1. 50.0% 2. 53.4% 3. 69.4% 4. 13.2% 5. 76.9%

The answer to your question is number 2.

Explanation:

Reaction

                                C₆H₆  +   Cl₂   ⇒   C₆H₅Cl   +  HCl

Molecular mass

C₆H₆ = (12 x 6) + (6 x 1) = 72 + 6 = 78 g

C₆H₅Cl = (12 x 6) + (5 x 1) + (1 x 35.5) = 112.5 g

Proportion

                           78 g of C₆H₆  -------------------  112.5 g of C₆H₅Cl

                           39 g of C₆H₆  ------------------    x

                           x = (39 x 112.5) / 78

                           x = 56.25 g of C₆H₅Cl

Percent yield =

Percent yield =

Percent yield = 53.33 %