a container with two gases is 27% oxygen. what is the partial pressure of oxygen if total pressure is 2.0
atm?

P(O) = 0.74 atm

Explanation:

Given data:

Amount of oxygen = 27%

Amount of second gas = X = 100-27 = 73%

Total pressure = 2.0 atm

Partial pressure of oxygen = ?

Solution:

Moles of oxygen = 27/100 = 0.27 mol

Moles of X = 73/100 = 0.73 mol

Partial pressure of oxygen:

P(O) = [n₁/ nt] P(total)

n₁ = moles of oxygen

nt = total number of moles (0.27 +  0.73)

P(O) = [n₁/ nt] P(total)

P(O) = [0.27/ 0.73] 2.0 atm

P(O) = 0.37 × 2.0 atm

P(O) = 0.74 atm