Synthesis of the activated form of acetate (acetyl‑coa) is carried out in an atp‑dependent process. acetate+coa+atp⟶acetyl−coa+amp+ppi acetate+coa+atp⟶acetyl−coa+amp+ppi the δ′∘δg′∘ for the hydrolysis of acetyl‑coa to acetate and coa is −32.2 kj/mol−32.2 kj/mol , and that for hydrolysis of atp to amp and ppippi is −30.5 kj/mol−30.5 kj/mol . calculate ? g’o for the atp –dependent synthesis of acetyl-coa.

a electronegativity decreases beacuse the size of nucleus is bigger.

the answer is c

tell me if wrong

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2