How many moles of oxygen are formed when 58.6 g of kno3 decomposes according to the following reaction? the molar mass of kno3 is 101.11 g/mol.

4 kno3(s) → 2 k2o(s) + 2 n2(g) + 5 o2(g)

First, convert the amount of KNO3 to moles using the molar mass:
58.6 g / 101.11 g/mol = 0.5796 mol KNO3

Next, using the given balanced reaction, use the stoichoimetric ratio to calculate the number of mole of oxygen that will be produced. From the reaction, for every 4 moles of KNO3 that decomposes, there are 5 moles of O2 formed. So,
0.5796 mol KNO3 x (5/4) = 0.7254 moles O2

Therefore, when 58.6 g of KNO3 decomposes, there are 0.7254 moles of O2 that will be formed.

It would be (at) + cu (s)