In the activity, click on the e∘cell and keq quantities to observe how they are related. use this relation to calculate keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. the two half-reactions that occur in the cell are cu2+(aq)+2e−→cu(s) and fe(s)→fe2+(aq)+2e− the net reaction is cu2+(aq)+fe(s)→cu(s)+fe2+(aq) use the given standard reduction potentials in your calculation as appropriate.

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Reduction at cathode :

Reduction potential of   to Cu=

Oxidation at anode:

Reduction potential of   to Fe=

To calculate the of the reaction, we use the equation:

Putting values in above equation, we get:

The standard cell potential of the reaction is 0.78 Volts.

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying