What is the specific heat of an object that weighs 15 g in changes temperature from 30 degrees celsius to 37 degrees c when 50 joules of heat is added

c = 0.48 j/ g.  °C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of object = 15 g

Change in temperature = 30 °C to 37°C

Heat absorbed = 50 J

Specific heat capacity = ?

Solution:

ΔT = 37 °C- 30 °C

ΔT = 7 °C

Now we will put the values in formula:

Q = m.c. ΔT

50 J = 15 g . c .  7 °C

c = 50 J / 105g. °C

c = 0.48 j/ g.  °C

answer

fusion: the energy source of stars. the energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. when the core is hot enough, nuclear fusion commences. fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

hope it

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